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Question: 1 / 400

To meet a fertilizer recommendation of 26 lbs of P, how many pounds of 10-20-10 should be applied per acre?

200

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130

To determine how many pounds of a 10-20-10 fertilizer are needed to meet a phosphorus recommendation of 26 pounds, it is essential to understand the composition of the fertilizer. The numbers in the fertilizer formula indicate the percentage of nitrogen (N), phosphorus (P), and potassium (K) respectively. In this case, the 10-20-10 indicates that 20% of the fertilizer weight is phosphorus.

To find out how much fertilizer needs to be applied to achieve the desired phosphorus amount, the calculation can be set up as follows:

1. Identify the percentage of phosphorus in the fertilizer, which is 20%.

2. Let \( X \) be the total pounds of fertilizer needed. Since 20% of \( X \) should equal 26 pounds of phosphorus, the equation can be written as:

\[

0.20 \times X = 26

\]

3. To isolate \( X \), divide both sides of the equation by 0.20:

\[

X = \frac{26}{0.20} = 130

\]

Thus, to achieve the recommended 26 pounds of phosphorus per acre, a total of 130 pounds of the 10

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